Determine the empirical formula for a compound that is made from 1.967g of carbon, 0.4115g of hydrogen, and 2.6205 g of oxygen. Put the formula in the order of carbon then hydrogen then oxygen. (Show work on scratch paper and upload in the last question. Write the formula without subscripts. For example C3H8O2 would be written C3H8O2)

  the volume of  0.220 m k2s    solution  required  to  completely  react with 175 ml  of 0.115m co(no3)2  calculate the moles  of co(no3)2 =  molarity x volume/1000175 x0.115/1000= 0.02  moleswrite  the reacting  equationk2s(aq)  +  co(no3)2  = 2 kno3(aq)  + cos(s)by  use  of mole ratio between k2s to co(no3)2 which  is  1: 1 the moles of k2s is therefore = 175  x0.115/1000= 0.02  molesvolume = moles/molarity=0.02/0.22=0.09  ml  of k2s

Abronsted lowry acid by donating a proton