Determine the molality of a solution in which 2.5 grams of glucose C12H22011 are dissolved in 1492grams of water. O a. 0.00
O b. 0.00
O C. 0.00
O d. 0.05

it's c (engineer's do their work with mechanical stuff not on any living being)

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol