H2SO4 + 2 NaOH → Na2SO4 + 2 H20
What mass of H2SO4 would be required to react with 2.25 mol of NaOH?

110.25grams

Explanation:

The balanced chemical equation is as follows:

H2SO4 + 2NaOH → Na2SO4 + 2H20

Based on the balanced chemical equation of the reaction given above, 1 mole of sulphuric acid (H2SO4) is required to react with 2 moles of sodium hydroxide (NaOH).

Hence, if 1 mol of H2SO4 is needed to react with 2 moles of NaOH

Then, 2.25mol of NaOH will be required to react with;

= 2.25/2

= 1.125mol of H2SO4

Using the formula, mole = mass/molar mass, we can convert the molar value of H2SO4 to its mass value.

Molar mass of H2SO4 = 1(2) + 32 + 16(4)

= 2 + 32 + 64

= 34 + 64

= 98g/mol

Therefore, mole = mass/molar mass

1.125 = mass/98

mass = 98 × 1.125

mass = 110.25grams of H2SO4

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