If 75 g. of Potassium Chloride (ionic compound) is dissolved in 250 grams of water, what will be the freezing point of the solution? Kf = 1.86

Explanation:

Hello there!

In this case, for these problem about the colligative property of freezing point depression, it is possible set up the following equation:

Whereas the van't Hoff's factor, i, is 2 since KCl is ionized in two ions (K+ and Cl-); and the molality (m) of the solution is computed by:

Thus, since the freezing point of water (ice) is 0°C, we obtain the following freezing point of the solution by plugging in:

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idk what the question is about

bcde is the incorrect answer it is a