Aluminum reacts with chlorine gas to form aluminum chloride according to the reaction below. 2 Al(s)
+
3 Cl2 (g)
2 AlCl3 (s)
How many moles of aluminum chloride can be produced from 2.12 L of chlorine gas at a
temperature of 24 °C and a pressure of 2.27 atm?

0.131mol

Explanation:

Firstly, we need to find the number of moles of chlorine gas (Cl2) by using the formula:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

Using PV = nRT

n of Chlorine = PV/RT

Based on the information provided in this question, V = 2.12 L, P = 2.27atm, T = 24°C = 24 + 273 = 297K

n = 2.27 × 2.12/ 0.0821 × 297

n = 4.8124/24.3837

n = 0.197

number of moles of Chlorine gas = 0.197mol

The balanced chemical equation provided in this question is as follows;

2 Al(s) + 3Cl2 (g) → 2AlCl3 (s)

3 moles of Cl2 produce 2 moles of AlCl3

0.197moles of Cl2 will produce;

0.197 × 2/3

= 0.394/3

= 0.131mol of AlCl3.

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

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