2KCIO3 -> 2KCI+ 302 How many moles of oxygen are produced by
the decomposition of 6.0 moles of potassium
chlorate, KCIO3?

9 moles

Explanation:

The balanced chemical equation for this decomposition reaction is as follows:

2KCIO3 → 2KCI+ 302

Based on this equation, 2 moles of potassium chlorate (KCIO3) decomposes to form 3 moles of oxygen gas (O2).

Hence, 6 moles of pottasium chlorate will decompose to produce;

6 × 3 ÷ 2

= 18 ÷ 2

= 9 moles of O2.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.

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