Calculate and compare the freezing points of the following aqueous solutions: 0.0500 m CaCl, and 0.0500 m
KCI. The freezing point depression constant, Ry, for water is 1.86 "C/mol.
A. The freezing points of both 0.050 m KC and 0.050 m CaCl, are the same namely, 0.186°C
B. The freezing point of 0.050 m KCl is - 0.279°C. The freezing point of 0.050 m Caci, is-0.186°C,
which is not as low as that of a potassium chloride solution of the same molality.
C. The freezing point of 0.050 m CoC, is 0.279°C. The freezing point of 0.050 m Klis-0.186"C.
which is not as low as that of a calcium chloride solution of the same molality.
D. The freezing points of both 0.050 m KCl and 0.050 m Cact, are the same namely,-0.279°C.
Answers: 2
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