Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3 Cl2(g) ⇌ S2Cl2(g) + CCl4(g) When 2.26 moles of CS2 and 3.95 moles of Cl2 are places in a 2L container and allowed to come to equilibrium, the mixture is found to contain 0.6 mol of CCl4. How many moles of Cl2 are present at equilibrium? What is the K value for this reaction?
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Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3 Cl2(g) ⇌ S2Cl2(g...
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