what is the percent of sulfur in sulfuric acid H2SO4? round your answer to the tenths place (1 decimal point)​

32.7%

Explanation:

To calculate the percentage by mass of an element in a compound, the following procedure is employed:

- Find the atomic mass of the element

- Find the molar mass of the compound

- Divide the atomic mass of the element by the molar mass of the compound and multiply by 100

Mathematically; this is denoted by:

Mass % of Sulphur = (Atomic mass of S/Molar mass of H2SO4) × 100

Atomic mass of S = 32g/lol

Molar mass of H2SO4 = 1(2) + 32 + 16(4) = 2 + 32 + 64

= 98g/mol

Hence,

% mass of S = 32/98 × 100

= 0.3265 × 100

= 32.65

= 32.7 (1 d.p)

Therefore, the percent of sulfur in sulfuric acid (H2SO4) is 32.7%

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !