How many moles are contained 80.3 gram of sm(no3)3

0.239 mol Sm(NO₃)₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 80.3 g Sm(NO₃)₃

[Solve] moles Sm(NO₃)₃

Step 2: Identify Conversions

[PT] Molar Mass of Sm - 150.36 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃