Calculate the volume occupied by 2.00 moles of H2 at 300.0 Kand 1.25
atm

39.4 Liters

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question;

P = 1.25atm

V = ?

T = 300K

n = 2.00mol

Using PV = nRT

V = nRT/P

V = (2 × 0.0821 × 300) ÷ 1.25

V = 49.26 ÷ 1.25

V = 39.41

V = 39.4 Liters

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