How many grams of AgCl are produced from 10.0 g AgNO3?

Equation of Reaction = AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)

Steps:

1. Find the moles of AgNO3 with formula n= Mass/Mr (molecular mass)

so you will get moles= 10.0/ 169.87 = 0.05886854654

2. Using stoichiometry you know the equation has 1 mole so the moles of AgCl are gonna be the same; therefore, you will use again the same formula.

3.  moles= mass/molecular mass

0.05886854654 = x/ 143.32

You rearrange the formula to find the mass

so mass = moles x molecular mass

mass = 0.05886854654 x 143.32

mass= 8.44 grams

Explanation:

c. orbital shape i hope this is correct