Ammonia (NH3) dissolved in water is heated in a beaker. If initially there had been 60 grams dissolved in 100 grams of water, what would happen if the temperature reached 90℃ and why? A. The solution would become supersaturated and the ammonia would all remain dissolved . B. The solution would become saturated but the amount of ammonia dissolved would remain the same . C. about 50 more grams of ammonia would be able to dissolve as the solution has become unsaturated . D. about 50 grams of ammonia would come out of solution as the temperature caused the solubility to decrease .

C. About 50 more grams ammonia would be able to dissolve as the solution has become unsaturated

Explanation:

From the question, we have;

The mass of ammonia dissolved in water = 60 grams

The mass of the water solvent which dissolves the ammonia = 100 g

The temperature to which the ammonia water solution is raised = 90°C

Therefore, given that the solubility of a solute in a solvent increases with temperature, when the temperature is raised, we have, that the solution will more unsaturated and will be able to dissolve more ammonia, therefore, option 'C' is the most correct option that corresponds with the relationship of temperature and solubility

a electronegativity decreases beacuse the size of nucleus is bigger.

the correct answer would be b) volume versus temperature, because they are also directly proportional.