A person throws a shot put from height of 5 feet with an initial vertical velocity of 40 feet per second. Use the vertical motion
model, h = -16t2 + vt + s, where v is the initial velocity in
feet per second and s is the initial height in feet, to calculate
the amount of time the shot put is in the air before it hits the
ground

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied