Suppose a 14-gram sample of iron is heated from 20.0°c to 25.0°c. the specific heat of iron is 0.11 cal/g°c. how much heat energy was absorbed by the iron? 38.5 cal 7.7 cal 636 cal 69.3 cal

Answer : The heat energy absorbed by the iron is 7.7 cal.

Explanation :

Formula used :

where,

Q = heat absorb = ?

m = mass of iron = 14 g

c = specific heat of iron =

= change in temperature

= initial temperature =

= final temperature =

Now put all the given value in the above formula, we get:

Therefore, the heat energy absorbed by the iron is 7.7 cal.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

the answer is na (sodium)