How many grams are needed to prepare 750. mL of a 0.35 M solution of NaOH?

10.5grams

Explanation:

Molarity = number of moles (n)/ volume (V)

According to this question;

Volume = 750 mL = 750/1000 = 0.75L

Molarity = 0.35M

number of moles (n) = molarity × volume

n = 0.35 × 0.75

n = 0.2625mol

Using mole = mass/molar mass

Molar Mass of NaOH = 23 + 16 + 1

= 40g/mol

mole = mass/molar mass

0.2625 = mass/40

mass = 10.5grams

10.5 grams are needed to prepare 0.75L of a 0.35 M solution of NaOH.