Iron(III) oxide and hydrogen react to form iron and water, like this:
Fe2O3 + 3H2 → 2Fe + 3H2O
At a certain temperature, a chemist finds that a 5.4L reaction vessel containing a mixture of iron(III) oxide, hydrogen, iron, and water at equilibrium has the following composition:
Compound Amount
Fe2O3 3.54g
H2 3.63g
Fe 2.37g
H2O 2.13g
Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits.
Answers: 1
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Iron(III) oxide and hydrogen react to form iron and water, like this:
Fe2O3 + 3H2 → 2Fe + 3H2O
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