1000 900
860
700
660
505
460
300
200
100
30
60
96
120 150 180 210 296 270 3000
Ad
Using your graph, answer questions 2-4.
VAT
2. What is the student's average speed for the whole trip? (71, 6C)
Given:
Ad =
At =
Vor-

the answer is a for sure mark brainliest i had got this right on usatestprep

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally