How many joules of heat are absorbed to raise the temperature of 125 grams of water at 1 atm from 35°C to its boiling point, 100.°C.

33962.5 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 125 g

Initial temperature (T₁) = 35 °C

Initial temperature (T₂) = 100 °C

Specific heat capacity (C) = 4.18 J/gºC

Heat (Q) absorbed =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = 35 °C

Initial temperature (T₂) = 100 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 35

ΔT = 65 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 125 g

Change in temperature (ΔT) = 65 °C

Specific heat capacity (C) = 4.18 J/gºC

Heat (Q) absorbed =?

Q = MCΔT

Q = 125 × 4.18 × 65

Q = 33962.5 J

Therefore, the heat absorbed is 33962.5 J

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell

points

explanation: