Chemistry, 22.03.2021 22:10 aletadaboss
.5 g of a substance dissolved in 125 g CCl4 leads to an elevation of the boiling point of 0.65 K. Calculate the freezing point depression, the molecular mass of the substance, and the factor by which the vapor pressure of CCl4 is lowered. Note, for CCl4, the freezing temperature is 250.3 K, the freezing point depression constant KF is 30 K kg/mol, the boiling temperature is 349.8 K, and the boiling point elevation constant KB is 4.95 K kg/mo
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.5 g of a substance dissolved in 125 g CCl4 leads to an elevation of the boiling point of 0.65 K. Ca...
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