Given the equation: 3Mg(S) + 2(NH4)3BO3(aq) → Mg3(BO3)2(aq) + 6NH4(aq) How many moles of Mg(s) will you need to completely react with 1.0mol of (NH4)3BO3(aq)? 1.5mol Mg
1.25mol Mg
1.75mol Mg
2.0mol Mg

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since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.