Chemistry, 19.03.2021 18:10 Jennifer312332
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A helicopter moves with a constant velocity v, = 4 m/s from point A to point B during a time
interval tas = 10 s. It then accelerates from point B to point with constant acceleration a, -
2m/s2 for a time interval tpc = 20 s. The average velocity of this helicopter for the whole trip is
equal to:
H
tab=10 s
V =4 m/s
A
B Ð’
tac= 20 s
az= 2m/s2​
Answers: 1
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