How many moles of O are in 12.6 mol Fe(NO3)3? The answer is 113.4, rounded is 113
Explanation: Just multiply 12.6 mol Fe(NO3)3 by 9 ( 9 is the number of O atoms in the equation)

There are 113 moles of O in 12.6 moles of

Explanation:

Given : moles of = 113.4

To find : moles of O = ?

1 mole of contains = 9 moles of O atoms

Thus 12.6 mole of contains = moles of O atoms

Thus there are 113 moles of O in 12.6 moles of

i'm pretty sure it is letter c.) car

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.