2 CH3OH + 3 02 2 CO2 + 4H2O What is the mass of oxygen (O2) that is required to produce 579 g of carbon dioxide (CO2)?
. Your answer should have three significant figures.

632 g

Explanation:

First we convert 579 g of CO₂ into moles, using its molar mass:

Then we convert CO₂ moles into O₂ moles, using the stoichiometric coefficients:

Finally we convert O₂ moles into grams, using its molar mass:

dynamic equilibrium is the answer.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml