Calculate the molarity of a solution that contains 85.0 g of Zn(C2H3O2)2 in 250. mL of solution (don't forget to convert mL to L first). Round to the nearest hundredth.

[Zn(C₂H₃O₂)₂] = 1.85M (3 sig-figs accurate to 0.01 Molar)

Explanation:

Concentration is defined as amount of solute in a specified volume of solution. That is, Concentration = mass of solute/volume of solution (solution = solute + solvent). When concentration is in terms of Molar values the essential relationship is Molarity(M) = moles solute / volume of solution in liters.

For this problem => first, convert mass of Zn(C₂H₃O₂)₂ into moles and then the volume of solution into liters. Take ratio of moles/volume of solution (L).

=> Molar Concentration = moles of Zn(C₂H₃O₂)₂ / Liters of solution

moles of Zn(C₂H₃O₂)₂ = 85.0 grams Zn(C₂H₃O₂)₂ / formula weight of Zn(C₂H₃O₂)₂  =  85.0g/183.5g·mole⁻¹ = 0.463 mole Zn(C₂H₃O₂)₂.

Volume of solution in Liters = 250ml / 1000ml/L = 0.250 liters

Molarity of  Zn(C₂H₃O₂)₂ solution = 0.463 mole Zn(C₂H₃O₂)₂  /0.250 liters of solution = 1.85 Molar in Zn(C₂H₃O₂)₂

Note: The symbiology convention for 'molar solution concentration' is to place brackets around the molecular formula. That is, [Zn(C₂H₃O₂)₂] = 1.85M

answer: any goods being imported from another country may be subject to issued by the federal government are tariffs

explanation:  

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them