Calculate the volume of 5.0 grams of NO gas at STP.

The volume of  5.0 g CO  2  is  2.6 L CO  2  at STP

Explanation:

STP

STP is currently  

0

∘

C

or  

273.15 K

, which are equal, though the Kelvin temperature scale is used for gas laws; and pressure is  

10

5

.

Pascals (Pa)

, but most people use  

100 kPa

, which is equal to  

10

5

.

Pa

.

You will use the ideal gas law to answer this question. Its formula is:

P

V

=

n

R

T

,

where  

P

is pressure,  

V

is volume,  

n

is moles,  

R

is a gas constant, and  

T

is temperature in Kelvins.

Determine moles

You may have noticed that the equation requires moles  

(

n

)

, but you have been given the mass of  

CO

2

. To determine moles, you multiply the given mass by the inverse of the molar mass of  

CO

2

, which is  

44.009 g/mol

.

5.0

g CO

2

×

1

mol CO

2

44.009

g CO

2

=

0.1136 mol CO

2

Organize your data

.

Given/Known

P

=

100 kPa

n

=

0.1136 mol

R

=

8.3145 L kPa K

−

1

mol

−

1

https://en.wikipedia.org/wiki/Gas_constant

T

=

273.15 K

Unknown:  

V

Solve for volume using the ideal gas law.

Rearrange the formula to isolate  

V

. Insert your data into the equation and solve.

V

=

n

R

T

P

V

=

0.1136

mol

×

8.3145

.

L

kPa

K

−

1

mol

−

1

×

273.15

K

100

kPa

=

2.6 L CO

2

rounded to two significant figures due to  

5.0 g

Answer link

Doc048

May 18, 2017

I got 2.55 Liters

Explanation:

1 mole of any gas at STP = 22.4 Liters

5

g

C

O

2

(

g

)

=

5

g

44

(

g

mole

)

=

0.114

mole

C

O

2

(

g

)

Volume of 0.114 mole  

C

O

2

(

g

)

= (0.114 mole)(22.4 L/mole) = 2.55 Liters  

C

O

2

(g) at STP

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally