how many moles of silver nitrate are needed to produce 6.75 moles of copper (II) nitrate upon reacting with excess copper?

13.50 moles of AgNO₃ are needed to produce 6.75 moles of Cu(NO₃)₂

Explanation:

We state the reactants:

AgNO₃

Cu

Then, the products are:

Cu(NO₃)₂

Ag

The reaction is:  2AgNO₃ + Cu  → 2Ag + Cu(NO₃)₂

Ratio is 1:2.

The copper is in excess, so the limiting reactant is the silver nitrate:

1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃

Then, 6.75 moles of copper (II) nitrate would be produced by, the double of moles

(6 75  . 2) /1  = 13.50 moles

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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