What is the volume, in liters, of 5.500 mol of C3H3 gas at STP

123.2 Liters.

Explanation:

At STP (T = 273K & P = 1atm), one mol of any gas will occupy 22.4 liters.

With the above information in mind, we can calculate how many liters would 5.500 mol of gas occupy:

5.500 mol * 22.4 L / mol = 123.2 L

So 5.500 moles of C₃H₃ would have a volume of 123.2 liters at STP.

the correct answer is:

a. formation of precipitation

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72