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Calculate the approximate volume of a 0.500 mol sample of gas at 15.0°C and a pressure of 1.20 atm. Show all steps to solve the problem

9.9L

Explanation:

Using the general gas law constant;

PV = nRT

Where;

P = pressure (atm)

V = volume (litres)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question; P = 1.20 atm, V = ?, T = 15°C = 15 + 273 = 288K, n = 0.5mol

Hence, using PV = nRT

V = nRT/P

V = 0.5 × 0.0821 × 288/1.20

V = 11.8224/1.2

V = 9.853

Volume = 9.9L

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