A paracetamol tablet was crushed and an excess of HCl 25cm³ of 1.0mol was added. the result of the solution was titrate against 0.5mol of NaOH. calculate the mass of CaCO3 in the paracetamol.​

1.35g of CaCO₃ are in the paracetamol

Explanation:

Assuming the volume of the 0.5mol NaOH was 23cm³

The CaCO₃ of paracetamol reacts with HCl as follows:

CaCO₃ + 2HCl → CO₂ + H₂O + CaCl₂

When an excess of HCl is added and titrated, we can find the moles of HCl that react = Moles CaCO₃ based on the second reaction:

NaOH + HCl → H₂O + NaCl

Moles added of NaOH:

23cm³ = 0.023L * (0.5mol / L) = 0.0115 moles NaOH = Moles HCl in excess

Moles of HCl:

25cm³ = 0.025L * (1.0mol / L) = 0.025 moles HCl

The moles of HCl that reacted = Moles CaCO₃ are:

0.025 moles - 0.115 moles = 0.0135 moles CaCO₃

The mass of CaCO₃ -Molar mass: 100.09g/mol- is:

0.0135 moles CaCO₃ * (100.09g/mol) =

answer; natural resources;

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?