Please help! asap i will give brainliest! Balancing Equations Worksheet
1) Na3PO4 + KOH → NaOH + K3PO4
2) MgF2 + Li2CO3 → MgCO3 + LiF
3) P4 + O2 → P2O3
4) RbNO3 + BeF2 → Be(NO3)2 + RbF
5) AgNO3 + Cu → Cu(NO3)2 + Ag
6) CF4 + Br2 → CBr4 + F2
7) HCN + CuSO4 → H2SO4 + Cu(CN)2
8) GaF3 + Cs → CsF + Ga
9) BaS + PtF2 → BaF2 + PtS
10) N2 + H2 → NH3
11) NaF + Br2 → NaBr + F2
12) Pb(OH)2 + HCl → H2O + PbCl2
13) AlBr3 + K2SO4 → KBr + Al2(SO4)3
14) CH4 + O2 → CO2 + H2O
15) Na3PO4 + CaCl2 → NaCl + Ca3(PO4)2
16) K + Cl2 → KCl
17) Al + HCl → H2 + AlCl3
18) N2 + F2 → NF3
19) SO2 + Li2Se → SSe2 + Li2O
20) NH3 + H2SO4 → (NH4)2SO

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the maximum mass of nh3 is nh3 in grams

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.