Find the molarity of a solution made by dissolving 12.5 g sodium carbonate in 500.0 mL total solution

The molarity of a solution is "25 M".

Explanation:

The given values are:

Moles of solute,

= 12.5 g

Volume of solution,

= 500 mL

i.e.,

= 0.5 L

Now,

The molarity will be:

=  

On substituting the values, we get

=  

=  

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.