Chemistry, 09.03.2021 14:00 OojohnnyoO116

How many grams of potassium chloride (KCl) can be produced from 180.6 g of chlorine (Cl2)?

Answers: 3

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Answers

Answer from: kenneth0125

379.79 g of KCl

Explanation:

The balanced equation for the reaction is given below:

Cl₂ + 2KBr —> Br₂ + 2KCl

Next, we shall determine the mass of Cl₂ that reacted and the mass of KCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Cl₂ = 70.90 g/mol

Mass of Cl₂ from the balanced equation = 1 × 70.90 = 70.90 g

Molar mass of KCl = 74.55 g/mol

Mass of KCl from the balanced equation = 2 × 74.55 = 149.1 g

SUMMARY:

From the balanced equation above,

70.90 g of Cl₂ reacted to produce 149.1 g of KCl.

Finally, we shall determine the mass of KCl produced by the reaction of 180.6 g of Cl₂. This can be obtained as follow:

From the balanced equation above,

70.90 g of Cl₂ reacted to produce 149.1 g of KCl.

Therefore, 180.6 g of Cl₂ will react to produce = (180.6 × 149.1)/70.90 = 379.79 g of KCl.

Thus, 379.79 g of KCl were obtained from the reaction.

Answer from: Quest

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 : $4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

equation 2 : $2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol$

equation 3 : $4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol$

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 : $4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol$

let us add equation 1 & 4

$4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

$4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol$

$4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol$

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

Answer from: Quest

Ch4 and ph3 are both covalent since they are composed both of non-metals. ch4 is non- polar because of london forces and has a geometry of tetrahedral ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf

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