If 5 times a number is increased by 4 the result is 19 find the lest possible number that satisfies theses condition

3

Explanation: 5 times a number would be 5x, then increase that by 4 is 5x+4.  The problem then says 5x + 4 ≥ 19.  If we solve for x then we get x ≥ 3 so x has to be greater than or equal to 3, so the smallest number it could be is 3.  You can even try any number smaller than 3 and see it doesn't work.  even something like 2.9

im pretty sure its b