What will the volume of 254 cm3 of gas be at STP if its original temperature is 72.6° C?

200.6cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question;

initial volume (V1) = 254cm³

final volume (V2) = ?

Initial temperature (T1) = 72.6°C = 72.6 + 273 = 345.6K

Final temperature (T2) = 273K

V1/T1 = V2/T2

254/345.6 = V2/273

Cross multiply

345.6 × V2 = 273 × 254

345.6V2 = 69342

V2 = 69342 ÷ 345.6

V2 = 200.6cm³

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.