A 102.5g sample of metal beads was heated in a water bath to 99.5°C. The metal was then added to the sample of water (25.7g) and the temperature of the water changed from an initial temperature of 20.0°C to a fi al temperature of 41.5°C. What was the temperature of the metal at equilibrium?
What was the temperature change of the metal?
Calculate the specific heat and the atomic mass of the model.
What is the metal?​

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml