H2SO4 + 2NaOH - H2O + Na2SO4 Use the balanced chemical equation to solve the following problems. Show all work and answer with the correct units and significant figures.
a. How many moles of sodium sulfate are produced if 13 g of sulfuric acid is used in the reaction?
b. How many molecules of water are produced if 2.0 g of sodium sulfate is produced in the above reaction?

c. What mass of sulfuric acid is required to completely react with 3.4 x 1024 formula units of sodium hydroxide?
Please help

Explanation:

The balanced equation for the reaction is given as;

2NaOH + H2SO4 → Na2SO4 + 2H2O  

a. How many moles of sodium sulfate are produced if 13 g of sulfuric acid is used in the reaction?

From the reaction;

1 mol of H2SO4 produces 1 mol of Na2SO4

Converting 13g of sulphuric acid to mol;

Number of moles = Mass /  Molar mass

Number of moles = 13g / 98.0785 g/mol

Number of moles = 0.1325 mol

Since the mol ratio is 1: 1. This means

0.1325 mol of sodium sulfate would be formed.

b. How many molecules of water are produced if 2.0 g of sodium sulfate is produced in the above reaction?

From the reaction;

1 mol of Na2SO4 is produced alongside  2 mol of H2O

Converting 2g of sodium sulfate mol;

Number of moles = Mass /  Molar mass

Number of moles = 2g / 142.04 g/mol

Number of moles = 0.01408 mol

Since the mol ratio is 1: 2. This means

0.02816 mol of water would be formed.

1 mol of water = 6.022×10^23 molecules

0.02816 mol = x

Solving for x;

x = 1.696 ×10^22 molecules

c. What mass of sulfuric acid is required to completely react with 3.4 x 1024 formula units of sodium hydroxide?

From the reaction;

1 mol of H2SO4 reacts with 2 mol of NaOH

1 mol = 6.022×10^23 units

x mol = 3.4 x 10^24 units

Solving for x;

x = 5.646 mol of NaOH

Since the mole ratio is 1:2;

5.646 mol / 2 = 2.823 mol of sulphuric acid

Converting too mass;

Mass = Number of moles * Molar mass

Mass = 2.823 mol * 98.0785 g/mol

Mass = 276.88 g

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