What is the molality of 151 grams of na2so4 dissolved in 547 g of water?

Molar mass Na2SO4 => 142.04 g/mol

Number of moles:

n = sample mass / molar mass

n = 151 / 142.04 => 1.063 moles

Mass of solvent in kilograms :

1 kg = 1000 g

574 g / 1000 = 0.574 kg

Therefore:

b = n solute / m solvent

b = 1.063 / 0.547

b = 1.943 mol/kg

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Olá. porque a reação na temperatura é muito rapida a do copo : )