The extraction of iron from ore is represented by the chemical reaction equation. Fe2O3 + 3CO → 2Fe + 3CO2
Calculate the mass of carbon (II) oxide required for the reduction of 40 kg of iron (III) oxide

21 Kg of CO.

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ + 3CO —> 2Fe + 3CO₂

Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:

Molar mass of Fe₂O₃ = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.

Thus, 21 Kg of CO is required for the reaction.

it's filtration, but this is an assumption so my apologies if i got this