For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
2 kclo3(s) → 2 kcl(s) + 3 o2(g)
a. 2.72 g kclo3
b. 0.361 g kclo3
c. 83.6 kg kclo3
d. 22.5 mg kclo3

Explanation:

Molar mass of = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of = 32.0 g

According to the equation, 2 moles of reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of as follows.

        of

(b) Calculate the amount of oxygen given by 0.361 g of as follows.

    of

c) Calculate the amount of oxygen given by 83.6 kg as follows.  

    of

Convert kg into grams as follows.

    = 32731 g of

(d) Calculate the amount of oxygen given by 22.5 mg of as follows.  

Convert mg into grams as follows.

  of

the increase of protons   hope this