Nitric oxide gas, NO(g), can be oxidized in air to produce nitrogen dioxide gas, NO2(g):
2 NO(g) + O2(g) → 2 NO2(g)
Determine the enthalpy change for this reaction
using any of these thermochemical equations:
O2(g) → 20(g)
AH = +495 kJ
NO(g) + O2(g) → NO2(g) + O2(g) AH = -199 kJ
203(g) → 302(g)
AH = -427kJ

iron and sleel

make siroeel

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

c. electrical charges of ionic bonds.

b.false that your answer