Consider the combustion of propane: C3H8 + 502 - 4 H2O + 3 CO2 AHzn =-2221 kJ/mol Cindy and her lab partner Lou have no clue what to do in their lab and are mimicking Billy and Susie. If Cindy and Lou have 1050 g of
propane (23.8 moles), calculate how much heat energy can they produce by burning their propane. Is that enough to melt their unobtanium?

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

yes

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