What's the empirical formula of 36.48% na 25.41% s 38.11% o

empirical formula is the simplest ratio of whole numbers of components making up a compound

the percentages have been given so we are finding masses for 100 g of the compound

Na S O

mass 36.48 g 25.41 g 38.11 g

number of moles

36.48 g/23 g/mol 25.41 g /32 g/mol 38.11 g / 16 g/mol

= 1.6 = 0.8 = 2.4

divide by the least number of moles

1.6 / 0.8 = 2 0.8/0.8 = 1 2.4 / 0.8 = 3

the number of atoms of each element

Na - 2

S - 1

O - 3

empirical formula is - Na₂SO₃

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.