How many grams of potassium bromide, KBr, are in 100mL of a 0.50 M solution?

5.95g

Explanation:

1 = 1000 mL

∴ 100 mL = 100 ÷ 1000 = 0.1

Volume = 0.1

Concentration = 0.5 M

Concentration =

0.5 =

No. of moles = 0.5 x 0.1 = 0.05 moles

No. of moles =

Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)

0.05 =

x = 119 × 0.05 = 5.95g

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.