and the measured absorbance of a sample solution is 0.367, what is the ferroin concentration in the measured solution

This question is incomplete, the complete question is;

If the detailed experimentally determined calibration curve is;

Absorbance = 12,100 M⁻¹ × [ferroin (M)] + 0.00230

and the measured absorbance of a sample solution is 0.367, what is the ferroin concentration in the measured solution?

Choice of Answer

A) 2.76 x 10⁻⁵ M

B) 3.01 x 10⁻⁵ M

C) 3.45 x 10⁻⁵ M

D) none of the above

the ferroin concentration in the measured solution is 3.01 × 10⁻⁵M

Option B) 3.01 x 10⁻⁵ M is the correct Answer

Explanation:

Given the data in the question;

Absorbance = 12,100 M⁻¹ × [ferroin (M)] + 0.00230 let this be equation 1

Measured Absorbance = 0.367

so, we simply substitute value of measured absorbance into equation 1

0.367 = 12,100 × [ferroin] + 0.00230

solve for [ferroin ]

0.367 = 12,100  × [ferroin] + 0.00230

12,100 × [ferroin]  = 0.367 - 0.00230

12,100 × [ferroin ]  = 0.3647

[ferroin ]  = 0.3647 / 12,100

[ferroin ]  = 3.014 × 10⁻⁵ ≈ 3.01 × 10⁻⁵M

Therefore,  the ferroin concentration in the measured solution is 3.01 × 10⁻⁵M

Option B) 3.01 x 10⁻⁵ M is the correct Answer

the answer is d   for sure : )

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.