Use the following masses of reactants and products to write balanced symbol equations. a) 81.2 g of butane (C4H10) reacts with 291.2 g of oxygen to produce 246.4 g of carbon dioxide and 126.0 g of water.

Density because it’s holyyy

What does that mean you dum bum

Catalysts and intermediateshope i

Moles of co₂ = 2.35/44 = 0.0534 mole.from ideal gas equation pv=nrt,  t = 18+273k = 291 kelvin.∴px5 = 0.0534x0.0821x291∴p = 0.0534x0.0821x291/5 = 0.2551 atm.now, 1 atm = 760 mm of hg  ∴ 0.02551 atm = 0.02551 x 760 = 19.38 mm of hg