For many purposes we can treat methane (CH4 as an ideal gas at temperatures above its boiling point of -161. °C Suppose the temperature of a sample of methane gas is raised from -19.0 °C to 12.0 °C, and at the same time the pressure is changed. If the initial pressure was 5.6 atm and the volume decreased by 50.0%, what is the final pressure? Round your answer to the correct number of significant digits.

The final pressure is 12.6 atm

Explanation:

The combined gas equation is,

where,

= initial pressure of gas = 5.6 atm

= final pressure of gas = ?

= initial volume of gas = v

= final volume of gas =

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

The final pressure is 12.6 atm

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current