For many purposes we can treat methane (CH4 as an ideal gas at temperatures above its boiling point of -161. °C Suppose the temperature of a sample of methane gas is raised from -19.0 °C to 12.0 °C, and at the same time the pressure is changed. If the initial pressure was 5.6 atm and the volume decreased by 50.0%, what is the final pressure? Round your answer to the correct number of significant digits.

The final pressure is 12.6 atm

Explanation:

The combined gas equation is,

where,

= initial pressure of gas = 5.6 atm

= final pressure of gas = ?

= initial volume of gas = v

= final volume of gas =

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

The final pressure is 12.6 atm

i believe it is c.) 1575 j.

the temperature of the gas, in k, not celsius.