How many moles of water (H2O) are produced when 2 moles of KMnO4 react with plenty of HCl? 2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

A. 2

B. 16

C. 8

D. 5

16

Explanation:

2 KMnO4 (aq) + 16 HCl (aq) → 2 MnCl2 (aq) + 2 KCl (aq) + 5 Cl2 (g) + 8 H2O (l)

This is an oxidation-reduction (redox) reaction:

2 MnVII + 10 e- → 2 MnII (reduction)

10 Cl-I - 10 e- → 10 Cl0 (oxidation)

KMnO4 is an oxidizing agent, HCl is a reducing agent.

This is a gas evolution reaction, Cl2 is the formed gas.

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