2NH3+2O2- N2O+3H2O If 80.0 grams of O2 reacted in above reaction ,how many grams of N2O will be produced?

55.0125 grams NO2

Explanation:

So we have 80 grams of O2, first convert to moles

80 g O2 * 1 mol/32 g O2 = 2.5 mol O2

Next use the mole ratio of O2 to NO2

2.5 mol O2* 1 mol NO2/2 mol NO2=1.25 mol NO2

Since the question is asking how many grams, convert NO2 to grams

1.25 mol NO2 * 44.01 NO2/1 mol NO2= 55.0125 grams

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer