A sample of an oxide of nitrogen is found to contain 30.4% nitrogen. What is its empirical formula?

If nitrogen = 30.4% then oxygen = 100-30.4 = 69.6%

divide each % value by atomic mass

N = 30.4/14 = 2.17

O = 69.6/16 = 4.35

Divide each y smaller:

N = 2.17/2.17 = 1

O = 4.35/2.17 = 2

Explanation:

the answer is a

photosynthesis

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol